Question

How do you simplify `(10)^-2 - (-10)^-2`?

Answer 1

`(10)^(-2)-(-10)^(-2)=0`

Explanation:

As `a^(-m)=1/a^m` and if n is an even integer `(-a)^n=a^n`. Hence

`(10)^(-2)-(-10)^(-2)`

= `(10)^(-2)-(10)^(-2)`

= `1/10^2-1/10^2`

= `0`