How do you multiply (4x^2 – 9)(8x^2 + 3)?

1 Answer
Jul 12, 2016

The expanded form will be: 32x^4 -60x^2 + 27.

Explanation:

This problem requires an understanding of the distributive property of multiplication:
(a + b)c = ac + bc

Using this rule we can manipulate the polynomial as follows:
(4x^2 – 9)(8x^2 + 3)
= 4x^2(8x^2 + 3) – 9(8x^2 + 3)
= 32x^4 + 12x^2 - 72x^2 +27
= 32x^4 -60x^2 + 27