How many "g" of water are required to be mixed with "11.75 g" of HgCl in order to make a "0.01 m" solution?
1 Answer
4,980 g
Explanation:
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We know the molality (m), but not the number of moles of solute. The mass of solute can be converted into moles using the molar mass of HgCl (236.04 g/mol) as a conversion factor:
Since the moles of solute and molality are known, we can rearrange the equation to solve for mass of solvent :
Lastly, the mass of solvent has to be converted from kg to g using the following conversion factor:
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Therefore,
4,980 g