The bases on a playground baseball diamond form a square, 60ft on a side. How far would a catcher standing n home plate need to throw the ball to get a runner out at second base?

1 Answer
Jul 13, 2016

84.85feet

Explanation:

The line from home plate to second base forms the hypotenuse of right triangle. The two sides of the triangle are each 60feet. Using the Pythagorean theorem, we can find the length of the hypotenuse:

602+602=c2

= 3600+3600=c2

= 7200=c2

7200=84.85

Therefore, the distance that the catcher will need to throw the ball to get a runner out at second base is 84.85feet.