Question

How do you solve and write the following in interval notation: `-3x <= -x^2`?

Answer 1

`x in [0, 3]`

Explanation:

If `(x-a)(x-b)<0`, then `x in (a, b).`. In other words, x is in between a

and b.

Here, ,

`x(x-3)<=0`.

So, x and (x-3) should have opposite signs for `x(x-3)<0`

And so, `x in [0, 3]`.