How do you solve and write the following in interval notation: $-4<a + 2<10$ ?

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Answer 1 · 2016-07-14T14:03:02

$a in ]-6,8[$

you can subtract 2 to all terms:

$-6< a<8$

Answer 2 · 2016-07-14T14:07:44

$-6 < a < 8$ ; $(-6,8)$

Subtract two.

$-4 < a + 2 < 10$

$-4 -2 < a + 2 -2<10-2$

$-6 < a < 8$

Interval Notation:

$(-6,8)$

Parenthesis do not include values, and brackets include the values they cover in interval notation.

How do you solve and write the following in interval notation: -4<a + 2<10-4<a + 2<10?