How do you solve and write the following in interval notation: #-4<a + 2<10#?

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Answer 1 · 2016-07-14T14:03:02

#a in ]-6,8[#

you can subtract 2 to all terms:

#-6< a<8#

Answer 2 · 2016-07-14T14:07:44

#-6 < a < 8#; #(-6,8)#

Subtract two.

#-4 < a + 2 < 10#

#-4 -2 < a + 2 -2<10-2#

#-6 < a < 8#

Interval Notation:

#(-6,8)#

Parenthesis do not include values, and brackets include the values they cover in interval notation.