Question

An object with a mass of `5 kg` is revolving around a point at a distance of `3 m`. If the object is making revolutions at a frequency of `19 Hz`, what is the centripetal force acting on the object?

Answer 1

I found `213kN`

Explanation:

You know that Centripetal Force is:
`F_C=mv^2/r`
Where
`v` is velocity;
`r` is the radius.
We need the velocity!
We can calculate it considering the length of the circumference decribed, i.e., `2pir` and divide it by the time `T` taken.
The time taken for a complete revolution, or period `T`, is given as:
`T=1/f=1/19s` where `f` is the frequency.
The velocity will then be:
`v=(2pir)/T=(2*pi*3)*19=358m/s`
So finally we have:
`F_C=mv^2/r=5(358)^2/3~~213kN`