How do you divide #(x^3-2x-6) / (x-3)#?

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Answer 1 · 2016-07-17T17:27:34

#x^2 +3x +7 # rem 15

Using synthetic division:
#(x^3 + 0x^2 - 2x -6) div (x-3)#

Use the coefficients.

#" | 1 0 -2 -6"#
#" 3 | 3 9 21"#

#" 1 3 7 15"#

"Multiply the 3 by each number at the bottom"

The answers are the coefficients from #x^2, x^1, x^0, and R#

#(x^3 + 0x^2 - 2x -6) div (x-3)#

=#1x^2 +3x +7 # rem 15