Question

How do you solve `x² - 8 = -7x`?

Answer 1

`x=1` or `x=-8`

Explanation:

`x^2-8=-7x`

`hArrx^2+7x-8=0`

`hArrx^2+8x-x-8=0`

`hArrx(x+8)-1(x+8)=0`

`hArr(x-1)(x+8)=0`

And hence either `x-1=0` i.e. `x=1` or

`x+8=0` i.e. `x=-8`.