How do you find the product of #(t+4)(t-3)#?

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Answer 1 · 2016-07-19T03:05:59

Use the distribution property.

In the destitution property each part of the parenthesis must be multiply by each part of the other parenthesis.

So multiply #t# times #t# and #t# times #-3#. This gives

#t * (t-3) = t^2 - 3t#

Then multiply #+4# times #t# and #+ 4# times #-3#. This gives

#4 * (t-3) = 4t -12#

Last add #4t# and #-3t# resulting #+t#. The complete answer is

#t^2 + t -12#