Question

What is the distance,in units, between (3, -5) and (8, 7) in the coordinate plane?

Answer 1

`13unit`.

Explanation:

The Distance `AB`, btwn. pts `A(x_1,y_1) and B(x_2,y_2)` is

`AB=sqrt{(x_1-x_2)^2+(y_1-y_2)^2}`

Hence, reqd. dist.

`=sqrt{(3-8)^2+(-5-7)^2}=sqrt(25+144)=sqrt169=13unit`.