How do you solve #(2x+5)^2=(2x+3)^2#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Deepak G. Jul 25, 2016 #x=-2# Explanation: #(2x+5)^2=(2x+3)^2# or #(2x)^2+2(2x)(5)+(5)^2=(2x)^2+2(2x)(3)+(3)^2# or #4x^2+20x+25=4x^2+12x+9# or #4x^2+20x+25-4x^2-12x-9=0# or #20x-12x+16=0# or #8x+16=0# or #8x=-16# or #x=-16/8# or #x=-2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 4133 views around the world You can reuse this answer Creative Commons License