How do you express sin(pi/ 6 ) * cos( (3 pi) / 2 ) without using products of trigonometric functions?
1 Answer
Jul 26, 2016
Explanation:
sin(pi/6) = 1/2
cos((3pi)/2) = 0
So:
sin(pi/6)*cos((3pi)/2) = 1/2*0 = 0