How do you express sin(π6)⋅cos(3π2) without using products of trigonometric functions?
1 Answer
Jul 26, 2016
Explanation:
sin(π6)=12
cos(3π2)=0
So:
sin(π6)⋅cos(3π2)=12⋅0=0
sin(π6)=12
cos(3π2)=0
So:
sin(π6)⋅cos(3π2)=12⋅0=0