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Answer 1 · 2016-07-27T05:57:01

#A(x)=8(x-3)#

The area function #A(x)="length" xx "width"#

Take note that length is represented by #f(x)=8#
Take note that width is represented by #x-3" "#the interval #[3, x]#

#A(x)=f(x)*(x-3)#

#A(x)=8*(x-3)#

The derivative of #A(x)#

#A(x)=8*(x-3)#

#A' (x)=d/dx(8x)-d/dx(24)=8-0=8#

There is a given constant function #f(x)=8#

It is confirmed that
#A' (x)=f(x)#

God bless....I hope the explanation is useful.