How do you factor completely #24r^2s^2 - 9t^2u^2#?

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Answer 1 · 2016-08-02T12:30:42

#3(8r^2s^2 - 3t^2u^2)#

Always look for a common factor first.

#24r^2s^2 - 9t^2u^2#

=#3(8r^2s^2 - 3t^2u^2)#

This does not factor further.

However, if the expression had been:

#25r^2s^2 - 9t^2u^2# we would have had difference of squares.

=#(5rs+3tu)(5rs-3tu)#