What is the period of f(θ)=tan(12θ7)sec(3θ8)?

1 Answer
Aug 3, 2016

112π3

Explanation:

Period of tan(12t7)7π12
Period of sec(3t8) --> (16pi)/3
Period of f(t) --> least common multiple of 7π12and16π3

7π12 ....x ( 64) ...--> 448π12=112π3
16π3 ...x (7) ...--> 112π3

Period of f(t) --> 112π3