How do I find the derivative of $ln(x^2)$ ?

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Answer 1 · 2016-08-03T09:15:37

Derivative of $lnx^2$ is $2/x$

We can use the chain rule for $(df(g(x)))/(dx)=(df)/(dg)xx(dg)/(dx)$

As here we have $f(x)=ln(x^2)$

$(dln(x^2))/(dx)=(dln(x^2))/(d(x^2))xx(dx^2)/(dx)$

= $1/x^2xx2x$

= $2x/x^2$

= $2/x$

Other way could be using formula for log and

$(dln(x^2))/(dx)=(d(2lnx))/(dx)=2(d(lnx))/(dx)=2/x$

How do I find the derivative of ln(x^2)ln(x^2)?