Question

How do you factor completely `3x^3-36x^2+96x`?

Answer 1

`3x(x-8)(x-4)`.

Explanation:

Observe that `3x` is common in every term. We take it out, & get,

The Expression `=3x(x^2-12x+32)`

`=3x{x^2-8x-4x+32}...............[8xx4=32, 8+4=12]`

`=3x{x(x-8)-4(x-8)}`

`=3x(x-8)(x-4)`.