Question

Two opposite sides of a parallelogram each have a length of `10`. If one corner of the parallelogram has an angle of `(3 pi)/4` and the parallelogram's area is `70`, how long are the other two sides?

Answer 1

`b=5`

Explanation:

Side `a=10` Angle `theta=3pi/4=135`
Area `=70` We have to find the other side `b=?`
Area of the parallelogram `=ab sin theta`
or
`ab sin theta=70`
or
`10b sin theta=70`
or
`b sin135=70/10`
or
`b/sqrt2=7`
or
`b=7 sqrt2`
or
`b=5`