What is the equation of the line with slope # m= -1/8 # that passes through # (7,-3) #?

2 Answers
Aug 4, 2016

#x+8y=-17#

Explanation:

#y=mx+c#
or
#-3=-7/8+c#
or
#c=-3+7/8#
or
#c=-(24+7)/8#
or
#c=-17/8#
So the equation is
#y=-x/8-17/8#
or
#8y=-x-17#
or
#x+8y=-17#

Aug 4, 2016

#y=-1/8x-17/8#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

here #m=-1/8" and " (x_1,y_1)=(7,-3)#

substitute these values into the equation.

#y-(-3)=-1/8(x-7)#

#rArry+3=-1/8x+7/8rArry=-1/8x+7/8-3#

#rArry=-1/8x-17/8" is the equation of the line"#