Two opposite sides of a parallelogram each have a length of #7 #. If one corner of the parallelogram has an angle of #( pi)/3 # and the parallelogram's area is #42 #, how long are the other two sides?

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Answer 1 · 2016-08-05T04:09:14

#b=6.93#

Area#=ab sin theta# where a=#7#;#theta=pi/3#
So we have
Area#=42=7b sin (pi/3)#
or
#b sin(pi/3)=42/7#
or
#b(0.866)=6#
or
#b=6.93#