How do you factor $2 x^{3} + x^{2} - 4 x - 2$ $2x^3 +x^2 - 4x -2$ ?

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Answer 1 · 2016-08-05T10:46:36

$= (2 x + 1) (x^{2} - 2)$ $=(2x+1)(x^2-2)$

$2 x^{3} + x^{2} - 4 x - 2$ $2x^3+x^2-4x-2$
$= x^{2} (2 x + 1) - 2 (2 x + 1)$ $=x^2(2x+1)-2(2x+1)$
$= (2 x + 1) (x^{2} - 2)$ $=(2x+1)(x^2-2)$

How do you factor 2x3+x2−4x−22x^3 +x^2 - 4x -2?