A rectangle has one corner in quadrant 1 on the graph of #y=16-x^2#, another at the origin, and the third on the positive y-axis, and the fourth on the positive x-axis. How do you express the area, A, of the rectangle as a function of x?

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Answer 1 · 2016-08-05T11:28:42

#x(16-x^2)#

for width x in the x direction, the rectangle's height is #y = 16 -x^2# so its area is

#x(16-x^2)#