Question

How do you write `9.002 times 10^-5` in standard notation?

Answer 1

In standard notation `9.002xx10^(-5)=0.00009002`

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of `10`.

In other words, in scientific notation, a number is written as `axx10^n`, where `1<=a<10` and `n` is an integer and `1<=a<10`.

To write the number in normal or standard notation one just needs to multiply by the power `10^n` (or divide if `n` is negative). This means moving decimal `n` digits to right if multiplying by `10^n` and moving decimal `n` digits to left if dividing by `10^n` (i.e. multiplying by `10^(-n)`).

In the given case, as we have the number as `9.002xx10^(-5)`, we need to move decimal digit to the left by five points. For this, let us write `9.002` as `000009.002` and moving decimal point five points to left means `0.00009002`

Hence in standard notation `9.002xx10^(-5)=0.00009002`

Answer 2

`0.00009002`

Explanation:

`9.002 xx 10^-5`

`=9 2/1000 xx 1/100000`

`=9002/1000 xx 1/100000`

`=9002.0/100000000`

shift the decimal point 8 places to the left.

`=0.00009002`