How do you write #9.002 times 10^-5 # in standard notation?

2 Answers
Aug 6, 2016

In standard notation #9.002xx10^(-5)=0.00009002#

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#.

In other words, in scientific notation, a number is written as #axx10^n#, where #1<=a<10# and #n# is an integer and #1<=a<10#.

To write the number in normal or standard notation one just needs to multiply by the power #10^n# (or divide if #n# is negative). This means moving decimal #n# digits to right if multiplying by #10^n# and moving decimal #n# digits to left if dividing by #10^n# (i.e. multiplying by #10^(-n)#).

In the given case, as we have the number as #9.002xx10^(-5)#, we need to move decimal digit to the left by five points. For this, let us write #9.002# as #000009.002# and moving decimal point five points to left means #0.00009002#

Hence in standard notation #9.002xx10^(-5)=0.00009002#

Jan 22, 2017

#0.00009002#

Explanation:

#9.002 xx 10^-5#

#=9 2/1000 xx 1/100000#

#=9002/1000 xx 1/100000#

#=9002.0/100000000#

shift the decimal point 8 places to the left.

#=0.00009002#