How do you simplify #(15y-15)/(3y^2+9y-12)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer Deepak G. Aug 6, 2016 #=5/(y+4)# Explanation: #(15y-15)/(3y^2+9y-12)# #=15(y-1)/(3(y^2+3y-4))# #=5(y-1)/(y^2+3y-4# #=5(y-1)/(y^2+4y-y-4)# #=5(y-1)/(y(y+4)-1(y+4)# #=5(y-1)/((y+4)(y-1))# #=5cancel(y-1)/((y+4)cancel(y-1))# #=5/(y+4)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 1417 views around the world You can reuse this answer Creative Commons License