How do you graph #g(x)=1/2log_3 (x+4)+3#?

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Answer 1 · 2016-08-06T16:49:25

Use the inverse relation #x = 9^g/729-4,, g=0, +-9, +-9^2, +-9^3, ...#

Inversion:

#3^(2g-6)=x+4#

#x=9^g/9^3-4=9^(g-3)-4#

Now, use the Table for# g = 0, +-9, +-9^2, +-9^3, +-9^4#

#(x, g) = ( 9^(g-3)-4#):::... #(5, 4) (-2, 3) ( -35/9, 2) (-522/81, 1)#

#... to (-4, -oo)#

oo)#

#x = -4# (downwards ) is asymptotic to the graph and #x >-4#....