How do you simplify #i(3+i)# and write the complex number in standard form?
1 Answer
Aug 10, 2016
Explanation:
First step is to distribute the bracket.
#rArri(3+i)=3i+i^2#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArri(3+i)=3i+i^2=-1+3i" in standard form"#
