Question

How do you solve the quadratic using the quadratic formula given `4a^2-8=a`?

Answer 1

`a =(-1+-sqrt(129))/8`

Explanation:

The quadratic formula takes an equation of the form `ax^2+bx+c=0` and gives us the solutions `x = (-b+-sqrt(b^2-4ac))/(2a)`.

Then, to use it, first we must work our equation into the desired form.

`4a^2-8=a`

`=>4a^2-a-8=0`

Now we have an equation of the desired form. Applying the formula:

`a = (-(-1)+-sqrt((-1)^2-4(4)(-8)))/(2(4))=(-1+-sqrt(129))/8`