Question

Two opposite sides of a parallelogram each have a length of `15`. If one corner of the parallelogram has an angle of `(5 pi)/12` and the parallelogram's area is `160`, how long are the other two sides?

Answer 1

`b=11`

Explanation:

Area of the parallelogram is `=ab sin theta` where `a=15` is the side and `theta=(5pi)/12` and we have to find `b=?`
Therefore
Area`=160=15b sin((5pi)/12)`
or
`bsin((5pi)/12)=160/15`
or
`b(0.966)=32/3`
or
`b=11`