Question

Two opposite sides of a parallelogram have lengths of `3`. If one corner of the parallelogram has an angle of `pi/8` and the parallelogram's area is `36`, how long are the other two sides?

Answer 1

`=31.36`

Explanation:

Area of the parallelogram is `=ab sin theta` where `a=3` is the side and `theta=(pi)/8` and we have to find `b=?`
Therefore
Area`=36=3b sin((pi)/8)`
or
`bsin((pi)/8)=36/3`
or
`b(0.383)=12`
or

`b=31.36`