How do you multiply #(5y-2)(5y+2)#?
2 Answers
Aug 18, 2016
25y^2-4#.
Explanation:
Using the Identity
Aug 18, 2016
Explanation:
We must ensure that each term in the 2nd bracket is multiplied by each term in the 1st bracket. This can be achieved as follows.
#(color(red)(5y-2))(5y+2)=color(red)(5y)(5y+2)color(red)(-2)(5y+2)# now distribute each pair of brackets and collect 'like terms'
#=25y^2+cancel(10y)-cancel(10y)-4=25y^2-4#