How do you find the exact value of #sin(0)#?

1 Answer
Aug 22, 2016

#sin0˚ = 0#

Explanation:

By the unit circle:

https://www.mathsisfun.com/geometry/unit-circle.html

As you can see, pairs are ordered in the manner of #(cos,sin)#. In other words, the #x# value is #cos# and the #y# value is #sin#.

Since in this problem we're dealing with the sine function, you can ask yourself: What is the y-value at #0˚#?

Well, the point at #0˚# is #(1, 0)#, and the #y# value here is 0. The hypotenuse, although measuring #1# unit, doesn't matter, because #0/a, a != 0#, always equals #0#, no matter the value of #a#. Hence, #sin0˚ = 0#.

Practice exercises:

#1.# Find the values of the variables in the following blank unit circle.

https://www.pinterest.com/pin/77616793549234244/ with adaptations

#2.# Determine the following exact values:

a) #sin240˚#

b) #cos(pi/2)#

c) #tan((7pi)/6)#

Hopefully this helps, and good luck!