How do you write the point slope form of the equation given (3,-8) and(7,-2)?

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Answer 1 · 2016-08-26T12:26:09

#y+8=3/2×(x-3)# or #3x-2y=25#

The slope of a line joining two points #(x_1,y_1)# and #(x_2,y_2)# is #(y_2-y_1)/(x_2-x_1)# and hence the equation is

#(y-y_1)=(y_2-y_1)/(x_2-x_1)×(x-x_1)#

Hence equation of line joining #(3,-8)# and #(7,-2)# in point-slope form is

#(y-(-8))=(-2-(-8))/(7-3)×(x-3)# or

#(y+8)=(-2+8)/4×(x-3)# or

#y+8=6/4×(x-3)# or

#y+8=3/2×(x-3)# or

#2y+16=3x-9# or

#3x-2y=25#