How do you multiply #(x-2)(x+6)=5x#?

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Answer 1 · 2016-08-28T02:30:10

#{4, -3}# is the solution set.

Start by multiplying out:

#=>x^2 - 2x + 6x - 12 = 5x#

Start simplifying:

#=>x^2 + 4x - 12 = 5x#

#=>x^2 - x - 12 = 0#

Solve by factoring:

#=>(x - 4)(x + 3) = 0#

#=>x = 4 and -3#

If you check in the original equation, you will find that both values of #x# work. Hence, our solution set is #{4, -3}#.

Hopefully this helps!