How do you solve for m in #K=1/2 m^2#?

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Answer 1 · 2016-08-29T06:48:13

#m= (2*K)^0.5#

Let me compute m step by step.

#m^2 = 2*K#

Now square root both sides:

#m = (2*K)^0.5#

Answer 2 · 2016-08-29T06:55:10

#m = +-sqrtK#

Isolate m, step by step. This is also called making #m# the subject of the formula.

It feels more comfortable to have #m# on the left hand side. We may just turn the equation around to achieve this.

#K = 1/2 m^2#

#1/2 m^2 = K color(white)(............................................) xx2#

#cancel2 xx 1/cancel2 m^2 = K xx2#

#m^2 = Kcolor(white)(............................................) "find" sqrt#

#m = +-sqrtK#