How do you factor #6x^2 - 25x + 14#?

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Answer 1 · 2016-08-30T18:02:23

#6x^2-25x+14=(3x-2)(2x-7)#

Given:

#6x^2-25x+14#

Use an AC Method:

Look for a pair of factors of #AC=6*14=84# which sum to #B=25#.

The pair #21, 4# works.

Use this pair to split the middle term and factor by grouping:

#6x^2-25x+14#

#=6x^2-21x-4x+14#

#=(6x^2-21x)-(4x-14)#

#=3x(2x-7)-2(2x-7)#

#=(3x-2)(2x-7)#