How do you write an equation of a line given point (-4,6) and m=8?

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Answer 1 · 2016-09-01T02:57:43

The equation for the given condition is:
#y# #-# #8x# #=# #38#

The general equation of a line is given by:
#y# #=# #m*x# #+# #c# ;or
This is when you have the #Slope# #(m)# and the #Intercept# #(c)# given.

If you have a point #(X,Y)# as in this case and the #slope# #(m)#, the general form is:
#(y-Y)# = #m# #*# #(x-X)#

So, for point #(-4,6)# and slope #m# #=# #8#, this gives
#(y-6)# #=# #8# #*# #(x-(-4))# ;or

#(y-6)# #=# #8# #*# #(x+4)# ;or

#(y-6)# #=# #8x# + #32# ;or

#y# #-# #8x# #=# #38#