How do you factor $x^{3} - x^{2} + 2 x - 2$ $x^3-x^2+2x-2$ ?

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Answer 1 · 2016-09-01T22:25:33

$(x - 1) (x^{2} + 2)$ $(x-1)(x^2+2)$

There are 4 terms, there is no common factor in all 4, so group them to make common factors. Make sure there is a + sign between the groups.

$x^{3} - x^{2} + 2 x - 2 = (x^{3} - x^{2}) + (2 x - 2)$ $x^3 - x^2 + 2x - 2 = (x^3 - x^2) + (2x - 2)$

= $x^{2} (x - 1) + 2 (x - 1) \leftarrow$ $x^2(x-1) + 2(x-1) larr$ there is a common bracket.

= $(x - 1) (x^{2} + 2)$ $(x-1)(x^2+2)$

How do you factor x3−x2+2x−2 x^3-x^2+2x-2?