How do you simplify #(6-5i)(4-i)#?
1 Answer
Sep 5, 2016
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(6-5i)(4-i)=24-6i-20i+5i^2#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr24-26i-5=19-26i# Thus
#(6-5i)(4-i)=19-26i#
