How do you solve #sqrt(x+2)=sqrt(x)#?

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Answer 1 · 2016-09-07T08:02:33

There is no solution to the equation. x is undefined.

Just looking at the equation you should get the feeling that there is something strange going on!

The square root of just x, cannot be the same as the square root of 2 more than x? Yet they are shown as equal?

Let's do the maths....

Square both sides.

#sqrt(x+2)^2 = sqrtx^2#

#x+2 = x#

#x-x = 0#

#0=2#

This is obviously FALSE and there is also no x term!

This is an indication that there is a problem with this equation.
There is no solution. There is no value of x. x is undefined.