How do you simplify #7i*3i(-8-6i)#?
1 Answer
Sep 8, 2016
Explanation:
The first step is to multiply 7i and 3i together.
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr7ixx3i=21i^2=-21#
#rArr-21(-8-6i)=168+126i#
