How do you simplify #-6i(8-6i)(-8-8i)#?
1 Answer
Sep 9, 2016
Explanation:
Before multiplying by - 6i , expand the brackets, using for example, the FOIL method.
#rArr(8-6i)(-8-8i)=-64-64i+48i+48i^2#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr(8-6i)(-8-8i)=-16i-112# and
#-6i(-16i-112)=96i^2+672i=-96+672i#