How do you simplify $(4 - 3 i) (6 - 6 i)$ $(4-3i)(6-6i)$ ?

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Answer 1 · 2016-09-11T15:47:28

$6 - 42 i$ $6-42i$

$4 \cdot 6 - 4 \cdot 6 i - 3 \cdot 6 i + 3 \cdot 6 i^{2} = 24 - 42 i - 18$ $4*6-4*6i-3*6i+3*6i^2=24-42i-18$

How do you simplify (4-3i)(6-6i)(4−3i)(6−6i)(4-3i)(6-6i)?