What is the density and specific gravity of 250 mL of krypton gas with a mass of 0.934 g?

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What is the density and specific gravity of 250 mL of krypton gas with a mass of 0.934 g?

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Answer 1 · 2016-09-13T04:52:13

$ρ ≅ 4 \cdot g \cdot L^{- 1}$ $rho~=4*g*L^-1$

Explanation:

$Density, ρ = \frac{Mass}{Volume}$ $"Density, "rho="Mass"/"Volume"$ $=$ $=$ $\frac{0.934 \cdot g}{0.250 \cdot L}$ $(0.934*g)/(0.250*L)$ $=$ $=$ $? ? g \cdot L^{- 1}$ $??g*L^-1$ .

Relative density relies on a reference substance, typically water.
$Relative Density = \frac{ρ_{substance}}{ρ_{water}}$ $"Relative Density"=rho_"substance"/rho_"water"$ , i.e. this is a dimensionless quantity. And $ρ_{water}$ $rho_"water"$ $=$ $=$ $1.0 \cdot g \cdot m L^{- 1}$ $1.0*g*mL^-1$ under most circumstances.

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What is the density and specific gravity of 250 mL of krypton gas with a mass of 0.934 g?

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