How do you write an equation in standard form when given slope and point on line (4, 1), m = -1/2?

2 Answers
Sep 14, 2016

The equation of the line is #y=-1/2x+3#

Explanation:

Let the equation of line is #y=mx+c or y= -1/2x+c ; (4,1)# is on the line. So # 1= -1/2*4 +c or c=3 #. Hence the equation of the line is #y=-1/2x+3# [Ans]

Sep 14, 2016

#y=-1/2x+3#

Explanation:

We can write the equation in #color(blue)"point-slope form"#

That is #color(red)(bar(ul(|color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

here #m=-1/2" and " (x_1,y_1)=(4,1)#

substitute these values into the equation.

#y-1=-1/2(x-4)#

distribute the bracket and simplify.

#y-1=-1/2x+2#

#y=-1/2x+2+1#

#rArry=-1/2x+3" is equation in standard form"#