What is the net area between #f(x) = 3x^2-x+2# and the x-axis over #x in [1, 3 ]#?
1 Answer
Sep 17, 2016
Net area
Explanation:
Given -
#f(x)=3x^2-x+2#
Area under the curve between
#int_1^3(3x^2-x+2)=[x^3-x^2/2+2x]_1^3#
#[3^3-3^2/2+2.3]-[1^3-1^2/2+2.1]#
#[27-9/2+6]-[1-1/2+2]#
#57/2-5/2=52-2=26#
Net area
