How do you write the equation of the cosine function with an amplitude of 2 and a period of 3pi/5?

1 Answer
Sep 17, 2016

#y=2cos(10/3x)#

Explanation:

The standard form of the #color(blue)"cosine function"# is

#color(red)(bar(ul(|color(white)(a/a)color(black)(y=acos(bx+c)+d)color(white)(a/a)|)))#

where amplitude = |a| and period#=(2pi)/b#

phase shift #=-c/b" and " d=" vertical shift"#

here amplitude = 2 and period #=(3pi)/5#

#rArrb=(2pi)/((3pi)/5)=2cancel(pi)xx5/(3cancel(pi))=10/3#

#rArry=2cos(10/3x)" is the equation"#