Question

How do you solve `4cosx=2`?

Answer 1

`x=2npi+-pi/3`

Explanation:

As `4cosx=2`

`cosx=2/4=1/2=cos(pi/3)`

As cosine is positive in first and fourth quadrant

`cosx==cos(+-pi/3)`

and is a function with a cycle of `2pi`.

`x=2npi+-pi/3`