How do you simplify #2^2/((2^3)^2*2^4)# and write it using only positive exponents?

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Answer 1 · 2016-09-17T17:55:41

#2^2/((2^3)^2*2^4)=1/2^8#

#2^2/((2^3)^2*2^4)#

= #2^2/(2^((2×3))*2^4)#

= #2^2/(2^6*2^4)#

= #(1×2^2)/(2^((6+4)))#

= #(1×2^2)/(2^((2+8)))#

= #(1×2^2)/(2^2×2^8)#

= #(1×cancel2^2)/(cancel2^2×2^8)#

= #1/2^8#