How do you simplify #2^2/((2^3)^2*2^4)# and write it using only positive exponents? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Shwetank Mauria Sep 17, 2016 #2^2/((2^3)^2*2^4)=1/2^8# Explanation: #2^2/((2^3)^2*2^4)# = #2^2/(2^((2×3))*2^4)# = #2^2/(2^6*2^4)# = #(1×2^2)/(2^((6+4)))# = #(1×2^2)/(2^((2+8)))# = #(1×2^2)/(2^2×2^8)# = #(1×cancel2^2)/(cancel2^2×2^8)# = #1/2^8# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1353 views around the world You can reuse this answer Creative Commons License